f(x)=x(x-1)(x-2)(x-3)(x-4) f'(1)=?
问题描述:
f(x)=x(x-1)(x-2)(x-3)(x-4) f'(1)=?
求详解
答
f'(1)=lim(x->1)[f(x)-f(1)]/(x-1)
=lim(x->1)[x(x-1)(x-2)(x-3)(x-4)]/(x-1)
=lim(x->1)[x(x-2)(x-3)(x-4)]
=1×(-1)×(-2)×(-3)
=-61