设y1=0.2x+1,y2=(2x+1)/3当x为何值时,y1,y2的绝对值相等
问题描述:
设y1=0.2x+1,y2=(2x+1)/3当x为何值时,y1,y2的绝对值相等
答
绝对值相同,有三种情况:0.2x+1=(2x+1)/3,0.2x+1=-(2x+1)/3,-(0.2x+1)=(2x+1)/3,这样求解X就好.
设y1=0.2x+1,y2=(2x+1)/3当x为何值时,y1,y2的绝对值相等
绝对值相同,有三种情况:0.2x+1=(2x+1)/3,0.2x+1=-(2x+1)/3,-(0.2x+1)=(2x+1)/3,这样求解X就好.