函数y=sin^2x+sinxcosx的最小正周期?
问题描述:
函数y=sin^2x+sinxcosx的最小正周期?
答
y=sin^2x+sinxcosx
=(1+cos2x)/2+(sin2x)/2
=(1/2)sin2x+(1/2)cos2x+1/2
=(√2/2)sin(2x+π/4)+1/2
T=2π/2=π