y=cos^4x-sin^4x的周期是 3Q
问题描述:
y=cos^4x-sin^4x的周期是 3Q
答
cos^4x-sin^4x
=(cos^2x-sin^2x)(cos^2x+sin^2x)
=cos^2x-sin^2x
=2cos^2x-1
=cos2x
所以周期为∏