函数f(x)=-tan(x+π/3)+1的定义域为多少?
问题描述:
函数f(x)=-tan(x+π/3)+1的定义域为多少?
答
x+π/3≠kπ+π/2
x≠kπ+π/6
即定义域为{x|x≠kπ+π/6,k∈Z}