y=√3sinx+cosx怎么到y=2sin(x+π/6)?

问题描述:

y=√3sinx+cosx怎么到y=2sin(x+π/6)?

(√3)^2+1=4
√4=2
y=2(√3/2sinx+1/2cosx)=2sin(x+π/6)