cos1°+cos2°+cos3°+...+cos179°化简
问题描述:
cos1°+cos2°+cos3°+...+cos179°化简
答
cos1°=-cos179°
同理,cos2°=-cos178°,cos3°=-cos177°
则cos1°+cos179°=0
原式可简化为0+cos90°=0