y=sin(2x+π/2)求导
问题描述:
y=sin(2x+π/2)求导
答
答:
y=sin(2x+π/2)=cos2x
y'(x)=-2sin2x
y=sin(2x+π/2)求导
答:
y=sin(2x+π/2)=cos2x
y'(x)=-2sin2x