（5-x）平方分之一,关于x的积分=什么?如题哈!

∫ 1/(5 - x)² dx
= - ∫ 1/(5 - x)² d(- x)
= - ∫ 1/(5 - x)² d(5 - x)
= - ∫ 1/u² du，u = 5 - x
= - (- 1/u) + C
= 1/(5 - x) + C
∫1/(5-x)²dx
=1/25∫1/(1-x/5)²dx
=1/5∫1/(1-x/5)²dx/5
令x/5=t
=1/5∫1/(1-t)²dt
=-1/5∫1/(1-t)²d(1-t)
=-1/5∫(1-t)^(-2)d(1-t)
=-1/5[-(1-t)^(-1)]+c
=1/[5(1-t)]+c
=1/(5 - x) + c

∫1/(5-x)²dx
=1/25∫1/(1-x/5)²dx
=1/5∫1/(1-x/5)²dx/5
令x/5=t
=1/5∫1/(1-t)²dt
=-1/5∫1/(1-t)²d(1-t)
=-1/5∫(1-t)^(-2)d(1-t)
=-1/5[-(1-t)^(-1)]+c
=1/[5(1-t)]+c
=1/(5 - x) + c

∫ 1/(5 - x)² dx
= - ∫ 1/(5 - x)² d(- x)
= - ∫ 1/(5 - x)² d(5 - x)
= - ∫ 1/u² du,u = 5 - x
= - (- 1/u) + C
= 1/(5 - x) + C