求∫dx/x(x²+1)积分?
问题描述:
求∫dx/x(x²+1)积分?
答
∫dx/x(x²+1)
=∫xdx/ x²(x²+1)
=0.5∫dx²/ x²(x²+1)
=0.5∫1/x² -1/(x²+1) dx²
=0.5lnx² - 0.5ln(x²+1) +C,C为常数