当x减y等于2时,求代数式(x减y)的二次方加2(y减x)加5的值
问题描述:
当x减y等于2时,求代数式(x减y)的二次方加2(y减x)加5的值
答
x-y=2
(x-y)²+2(y-x)+5
=(x-y)²-2(x-y)+5
=2²-2×2+5
=5
答
解析
x-y=2
(x-y)²+2(y-x)+5
=(x-y)²-2(x-y)+5
=4-2x2+5
=9-4
=5
希望对你1有帮助
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答
解
x-y=2
(x-y)²+2(y-x)+5
=(x-y)²-2(x-y)+5
=2²-2×2+5
=5