【(x+2y)(x-2Y)-(x-2y)²】÷4Y,其中x=2,y=½

问题描述:

【(x+2y)(x-2Y)-(x-2y)²】÷4Y,其中x=2,y=½

【(x+2y)(x-2Y)-(x-2y)²】÷4Y
=(x²-4y²-x²+4xy-4y²)÷4y
=(4xy-8y²)÷4y
=x-2y
当x=2,y=½时
原式=2-1=1

【(x+2y)(x-2Y)-(x-2y)²】÷4Y
=(x-2y)[(x+2y)-(x-2y)]
=(x-2y)×4y
=(2-2×½﹚×4×½
=1×2
=2