已知1/x+1/y=2,求(x+y+2xy+2y)÷(2xy+y)的值谢谢了,

问题描述:

已知1/x+1/y=2,求(x+y+2xy+2y)÷(2xy+y)的值谢谢了,

(x+y+2xy+2y)÷(2xy+y)=(x+y/2xy)+(2xy/2xy)+(2y/y) =x+y/2xy+3已知1/x+1/y=2 ∴x+y/2xy=1/2(1/X+1/y)=1/2×2=1 则原式=1+3=4