求定积分∫(0到π/2)(asinx+bcosx)dx
问题描述:
求定积分∫(0到π/2)(asinx+bcosx)dx
答
∫(0到π/2)(asinx+bcosx) dx
= ∫(0→π/2) (asinx + bcosx) dx
= -a * cosx + b *sinx (x = 0→π/2)
= a + b