已知点O在△ABC内部,且有OA+2OB+4OC=0,则△OAB与△OBC的面积之比为_.
问题描述:
已知点O在△ABC内部,且有
+2OA
+4OB
=0,则△OAB与△OBC的面积之比为______. OC
答
如图,作向量
=4OC′
,OC
=2OB′
,OB
=−OA′
.OA
则S△OBC=
S△OBC'=1 4
S△OB'C'=1 8
S△OB'A'=1 8
S△OB'A=1 8
S△AOB.1 4
故答案为4:1