已知点O在△ABC内部,且有OA+2OB+4OC=0,则△OAB与△OBC的面积之比为_.

问题描述:

已知点O在△ABC内部,且有

OA
+2
OB
+4
OC
=0,则△OAB与△OBC的面积之比为______.

如图,作向量

OC′
=4
OC
OB′
=2
OB
OA′
=−
OA

则S△OBC=
1
4
S△OBC'=
1
8
S△OB'C'=
1
8
S△OB'A'=
1
8
S△OB'A=
1
4
S△AOB
故答案为4:1