(a+b/a−b)2•2a−2b3a+3b-a2a2−b2÷a/b
问题描述：
(
)2•a+b a−b
-2a−2b 3a+3b
÷a2
a2−b2
a b
答
原式=
×(a+b)2 (a−b)2
-2(a−b) 3(a+b)
×a2 (a+b)(a−b)
b a
=
-2(a+b) 3(a−b)
ab (a+b)(a−b)
=
2(a+b)2−3ab 3(a+b)(a−b)
=
．2a2+ab+2b2
3(a+b)(a−b)
故答案为
．2a2+ab+2b2
3(a+b)(a−b)