cosx+根号3sinx=2cos(x-π/3)
问题描述：
cosx+根号3sinx=2cos(x-π/3)
答
cosx+根号3sinx
=2*[1/2cosx+(根号3)/2sinx]
=2*【sinπ/3*2cosx+ cosπ/3*sinx】
=2cos(x-π/3)
希望我的答案您能满意,