已知:2x+y=6,x-3y=1,求7y(x-3y)^2-2(3y-x)^2
问题描述:
已知:2x+y=6,x-3y=1,求7y(x-3y)^2-2(3y-x)^2
答
2x+y=6(1)
,x-3y=1, (2)
(2)*2-(1)
2x-6y-2x-y=2-6
7y=4
7y(x-3y)^2-2(3y-x)^2
=7y(x-3y)^2-2(x-3y)^2
=(7y-2)(x-3y)^2
=(4-2)*1^2
=2