已知1/a+1/b+1/c+1/d+1/36+1/45=1,且a,b,c,d为连续整数,求a,b,c,d.
问题描述:
已知1/a+1/b+1/c+1/d+1/36+1/45=1,且a,b,c,d为连续整数,求a,b,c,d.
答
1/a+1/b+1/c+1/d=19/20
1/3+1/4+1/5+1/6=19/20
所以a=3 b=4 c=5 d=6