已知对于f﹙x﹚有f﹙x+1﹚=3x³-4x²+5x-6,求f﹙x﹚
问题描述:
已知对于f﹙x﹚有f﹙x+1﹚=3x³-4x²+5x-6,求f﹙x﹚
答
f﹙x+1﹚=3x³-4x²+5x-6令 t=x+1则 x=t-1 代入f(t)=3(t-1)³-4(t-1)²+5(t-1)-6=3t³-9t²+9t-3-4(t²-2t+1)+5t-5-6=3t³-9t²+9t-4t²+8t+5t-18=3t³-13t²+22t-...