用因式分解法解方程. (1)x2=x (2)x2=x-1/4 (3)x-2=x(x-2)
问题描述:
用因式分解法解方程.
(1)x2=x
(2)x2=x-
1 4
(3)x-2=x(x-2)
答
(1)移项,得x2-x=0,
因式分解,得x(x-1)=0,
于是,得x=0,x-1=0,
x1=0,x2=1;
(2)移项,得x2-x+
=0,1 4
因式分解,得,(x-
)2=0,1 2
于是,得,x-
=0,1 2
x1=x2=
;1 2
(3)移项,得x(x-2)-(x-2)=0,
因式分解得,(x-2)(x-1)=0,
于是,得x-2=0,x-1=0,
x1=2,x2=1.