用因式分解法解方程. (1)x2=x (2)x2=x-1/4 (3)x-2=x(x-2)

问题描述:

用因式分解法解方程.
(1)x2=x
(2)x2=x-

1
4

(3)x-2=x(x-2)

(1)移项,得x2-x=0,
因式分解,得x(x-1)=0,
于是,得x=0,x-1=0,
x1=0,x2=1;
(2)移项,得x2-x+

1
4
=0,
因式分解,得,(x-
1
2
2=0,
于是,得,x-
1
2
=0,
x1=x2=
1
2

(3)移项,得x(x-2)-(x-2)=0,
因式分解得,(x-2)(x-1)=0,
于是,得x-2=0,x-1=0,
x1=2,x2=1.