y=2/(x^2-2x+2)的值域
问题描述:
y=2/(x^2-2x+2)的值域
答
x^2-2x+2=(x-1)^2+1≥1
则00值域(0,2]
y=2/(x^2-2x+2)的值域
x^2-2x+2=(x-1)^2+1≥1
则00值域(0,2]