对多项式(x^2-2x)(x^2-2x+2)+1进行因式分解.
问题描述:
对多项式(x^2-2x)(x^2-2x+2)+1进行因式分解.
答
(x^2-2x)(x^2-2x+2)+1=(x²-2x+1-1)(x²-2x+1+1)-1=【(x-1)²-1】【(x-1)²+1】+1=(x-1)四次方
答
(x^2-2x)(x^2-2x+2)+1
=(x²-2x)²+2(x²-2x)+1
=(x²-2x+1)²
=(x-1)^4