(x-3)^2+(√ X^2-6X+16)=13

问题描述:

(x-3)^2+(√ X^2-6X+16)=13

设(x-3)^2=y
y+√ (y+7)=13
y+7=169-26y+y^2
y^2-27y+162=0
y=9或18(舍去)
所以x=0或6