设函数f(x)=2x-cosx,{An}是公差为TT/8的等差数列,f(a1)+f(a2)+…f(a5)=5TT,则 f[(a3)]^2-a1a3=
问题描述:
设函数f(x)=2x-cosx,{An}是公差为TT/8的等差数列,f(a1)+f(a2)+…f(a5)=5TT,则 f[(a3)]^2-a1a3=
答
设函数f(x)=2x-cosx,{An}是公差为TT/8的等差数列,f(a1)+f(a2)+…f(a5)=5TT,则 f[(a3)]^2-a1a3=