logam/n=logam-logan
问题描述：
logam/n=logam-logan
答
1、因为n=log(a)(b),代入则a^n=b,即a^(log(a)(b))=b.
2、MN=M×N 由基本性质1(换掉M和N) a^[log(a)(MN)] = a^[log(a)(M)]×a^[log(a)(N)] 由指数的性质 a^[log(a)(MN)] = a^{[log(a)(M)] + [log(a)(N)]} 又因为指数函数是单调函数,所以 log(a)(MN) = log(a)(M) + log(a)(N)
3、与（2）类似处理 MN=M÷N 由基本性质1(换掉M和N) a^[log(a)(M/N)] = a^[log(a)(M)]÷a^[log(a)(N)] 由指数的性质 a^[log(a)(M/N)] = a^{[log(a)(M)] - [log(a)(N)]} 又因为指数函数是单调函数,所以 log(a)(M/N) = log(a)(M) - log(a)(N)
时间比较晚了,我直接给你拉答案过来了,我就不自己打了