ln(1+x^2)原函数怎么求
问题描述:
ln(1+x^2)原函数怎么求
答
∫ln(1+x^2) dx
= xln(1+x^2) - 2∫ [x^2/(1+x^2)] dx
= xln(1+x^2) - 2∫ dx + 2∫ dx/(1+x^2)
= xln(1+x^2) - 2x + 2arctanx + C