计算（a-2)(a^2+2a+4)= (2x-y)(4x^2+2xy+y^2)= 乘法公式：
问题描述：
计算（a-2)(a^2+2a+4)= (2x-y)(4x^2+2xy+y^2)= 乘法公式：
答
根据立方和(差)公式:(a±b)(a²+ab+b²)=a³±b³
(a-2)(a²+2a+4)
=a³-2³
=a³-8
(2x-y)(4x²+2xy+y²)
=(2x)³-y³
答
（a-2)(a^2+2a+4)=a(a²+2a+4)-2(a²+2a+4)=a³+2a²+4a-2a²-4a-8=a³-8(2x-y)(4x^2+2xy+y^2)=2x(4x²+2xy+y²)-y(4x²+2xy+y²)=8x³+4x²y+2xy²-4x²y...