2007x-2008y=2009,x+y=1,求4017x-4013y+4018的值?
问题描述:
2007x-2008y=2009,x+y=1,求4017x-4013y+4018的值?
答
4017x-4013y+4018
=2(2007x-2008y)+3(x+y)+4018
=2 * 2009 + 3 +4018
=4018 + 3 +4018
= 8039