复数z=(1-i)的平方×i得多少
问题描述:
复数z=(1-i)的平方×i得多少
答
z=(1-i)^2×i
= (-2i)xi
=-2i^2
=2
复数z=(1-i)的平方×i得多少
z=(1-i)^2×i
= (-2i)xi
=-2i^2
=2