y=(sin x)^lnx 对数求导
问题描述：
y=(sin x)^lnx 对数求导
答
y = (sinx)^lnxlny = (lnx) ln(sinx)(1/y) y' = (lnx) (1/sinx) cosx + (ln(sinx)) 1/x= (lnx) cotx + (1/x) lin(sinx)y' = [(lnx) cotx + (1/x) lin(sinx)]y= [(lnx) cotx + (1/x) lin(sinx)]((lnx) cotx + (1/x) l...y=x根号下(1-x)/(1+x) y=(x^2/1-x)*根号下(5-x)/(3+x)^2