(x-2)的二次方-(x+3)(x-3)=4x-1

问题描述:

(x-2)的二次方-(x+3)(x-3)=4x-1


(x-2)²-(x+3)(x-3)=4x-1
x²-4x+4-(x²-9)-4x+1=0
(x²-x²)+(-4x-4x)+(4+9+1)=0
-8x=-14
x=7/4