已知tan(π+α)=根号3tan(π/2-β),cos(3π/2+α)=-根号2cos(π+β),a∈(-π/2,π/2),β∈(0,π)求α,β
问题描述:
已知tan(π+α)=根号3tan(π/2-β),cos(3π/2+α)=-根号2cos(π+β),a∈(-π/2,π/2),β∈(0,π)求α,β
答
已知tan(π+α)=根号3tan(π/2-β),cos(3π/2+α)=-根号2cos(π+β),a∈(-π/2,π/2),β∈(0,π)求α,β