复数Z=a+(a+1)i(a∈R)是纯虚数,则Z^2是

问题描述:

复数Z=a+(a+1)i(a∈R)是纯虚数,则Z^2是

复数Z是纯虚数,则其实部为0,所以:a=0
Z=i,Z^2=-1.