已知A=(2cos^2x-1)/[(tan(派/4)-x)(sin^2(派/4)+x)](1)求A(2)当A=tanB,求4BA=(2cos^2x-1)/[(tan(派/4)-x)(sin^2[(派/4)+x)] ]

问题描述:

已知A=(2cos^2x-1)/[(tan(派/4)-x)(sin^2(派/4)+x)]
(1)求A
(2)当A=tanB,求4B
A=(2cos^2x-1)/[(tan(派/4)-x)(sin^2[(派/4)+x)] ]