若函数fx=2x+1分之1-x的值域是
问题描述：
若函数fx=2x+1分之1-x的值域是
具体方法!
答
f(x)=(-x-0.5+1.5)/[2(x+0.5)]=[-(x+0.5)+1.5]/[2(x+0.5)]=-(x+0.5)/[2(x+0.5)]+1.5/[2(x+0.5)]=-1/2+3/(4x+2)3/(4x+1)≠0所以-1/2+3/(4x+)≠-1/2所以值域(-∞,-1/2)∪(-1/2,+∞)