已知两点M(-2,0),N(2,0),点P满足PM•PN=12,则点P的轨迹方程为_.

问题描述:

已知两点M(-2,0),N(2,0),点P满足

PM
PN
=12,则点P的轨迹方程为______.

设P(x,y),则

PM
=(−2−x,−y),
PN
=(2−x,−y)

PM
PN
=12

∴(-2-x,-y)•(2-x,-y)=12,
整理,得x2+y2=16.
故答案为:x2+y2=16.