(x-y)(x2+xy+y2)
问题描述:
(x-y)(x2+xy+y2)
答
原式=x3+x2y+xy2-x2y-xy2-y3
=x3-y3.
(x-y)(x2+xy+y2)
原式=x3+x2y+xy2-x2y-xy2-y3
=x3-y3.