数列an,a1=4,Sn+S(n+1)=5/3an+1,an
问题描述:
数列an,a1=4,Sn+S(n+1)=5/3an+1,an
数列an,a1=4,Sn+S(n+1)=5(a(n+1))/3,求an
答
Sn+S(n+1)=5(a(n+1))/3因为S(n+1)=SN+A(N+1)所以Sn+SN+A(N+1)=5a(n+1)/32SN=2a(n+1)/3SN=a(n+1)/3S(N-1)=AN/3SN-S(N-1)=a(n+1)/3-AN/3=ANa(n+1)/3=4AN/3a(n+1)=4AN (n≥2)a1+a1+a2=5a2/38=2a2/3a2=...