1.6^p(p+q)^2-4p(p+q)^2
问题描述：
1.6^p(p+q)^2-4p(p+q)^2
2.x(x+y)^2(x-y)^2- x(x+y)^2
3.3(x-1)^3 y-(1-x)^3 z
4.0.5×3.7^2-3.7×2.7+0.5×2.7^2
答
1.6^p(p+q)^2-4p(p+q)^2
=（p+q)^2(6p-4p)
=2p(p+q)^2
2.x(x+y)^2(x-y)^2- x(x+y)^2
=x(x+y)^2[(x-y)^2-1]
=x(x+y)^2(x-y+1)(x-y-1)
3.3(x-1)^3 y-(1-x)^3 z
=3(x-1)^3 y+(x-1)^3 z
=(x-1)^3(3y+z)
=(x-1)(x^2+x+1)(3y+z)
4.0.5×3.7^2-3.7×2.7+0.5×2.7^2
=0.5(3.7^2-2x3.7x2.7+2.7^2)
=0.5(3.7-2.7)^2
=0.5x1^2
=0.5