如果X属于[0,派/3]!求函数f(x)=2sin(-3x+π/4)值域
问题描述:
如果X属于[0,派/3]!求函数f(x)=2sin(-3x+π/4)值域
答
x∈[0,π/3],-3x+π/4∈[-3π/4,π/4],
当x=,π/4时,-3x+π/4=-π/2,f(x)取最小值-2
当x=0时,-3x+π/4=π/4,f(x)取最大值√2
f(x)在定义域内是连续的
f(x)=2sin(-3x+π/4)的值域是[-2,√2]