如图直线y=-3/4x+6和y=3/4x-2交与点P.直线分别y=-3/4x+6交X轴,Y轴与AB直y=3/4x-2交Y轴于点C

问题描述:

如图直线y=-3/4x+6和y=3/4x-2交与点P.直线分别y=-3/4x+6交X轴,Y轴与AB直y=3/4x-2交Y轴于点C
1求两直线交点的坐标
2 求△PCA 的面积

1、∵y=-3/4x+6和y=3/4x-2交与点P.∴联立y=-3/4x+6和y=3/4x-2解得x=96/25,y=128/25即P(96/25,128/25)2、∵y=-3/4x+6与X轴交于A,∴A(8,0)∵y=3/4x-2与Y轴于点C∴C(0,-2)设过P、C两点的直线为y=kx+b则128/25=96/2...