如图,AB=AC,AD=AE,∠BAC=∠DAE.求证:△ABD≌△ACE.

问题描述:

如图,AB=AC,AD=AE,∠BAC=∠DAE.求证:△ABD≌△ACE.

证明:∵∠BAC=∠DAE,
∴∠BAC+∠CAD=∠DAE+∠CAD,
即∠BAD=∠EAC,
在△ABD和△ACE中

AB=AC
∠BAD=∠EAC
AE=AD

∴△ABD≌△ACE.