已知函数a满足a²+2a-8=0,求(1/a+1)-(a+3/a²-1)*(a²-2a+1/a²+4a+3)

问题描述:

已知函数a满足a²+2a-8=0,求(1/a+1)-(a+3/a²-1)*(a²-2a+1/a²+4a+3)

a²+2a-8=0
所以有(a+1)^2=9
a+1=3或a+1=-3
故a=2或a=-4
将a=2代入(1/a+1)-(a+3/a²-1)*(a²-2a+1/a²+4a+3)=
将a=-4代入(1/a+1)-(a+3/a²-1)*(a²-2a+1/a²+4a+3)=