计算(x²×x的n-1次方×x1+n次方)³的结果为

问题描述:

计算(x²×x的n-1次方×x1+n次方)³的结果为

(x²×x的n-1次方×x1+n次方)³
=(x的n+1次方×x1+n次方)³
=(x的2+2n次方)³
=x的6+6n次方