x²-x+n=(x+m)(x+4),则m,n的值为?

问题描述:

x²-x+n=(x+m)(x+4),则m,n的值为?

取x=0得n=4m,取x=1得n=5+5m,所以4m=5+5m,解得m=-5,n=-20

x^2-x+n=x^2+(4+m)x+4m
左右对照得
4+m=-1
m=-5
n=4m
n=-20