等差数列{an}中,公差d=1/2.且S100=145,则a1+a3+a5+.+a99=?
问题描述:
等差数列{an}中,公差d=1/2.且S100=145,则a1+a3+a5+.+a99=?
答
a1+a2+a3+……a100=145
a2 = a1+1/2;
a4 = a3+1/2;
……
a100 = a99+1/2;
所以有a1+(a1+1/2)+a3+(a3+1/2)+……+a99+(a99+1/2) = 145
到这里应该会算了吧