三角函数···

问题描述:

三角函数···
cos(π/5 +x) = -1/2 ,
怎么化简?

cos(π/5+x)=-1/2,则π/5+x=2kπ+2π/3或π/5+x=2kπ-2π/3,解得x=2kπ+7π/15或x=2kπ-13π/15.其中k是整数.还是看不懂厄 - -。就π/5+x=2kπ+2π/3或π/5+x=2kπ-2π/3怎么算的。 配方还是啥? 详细点么?余弦值等于-1/2的角是2kπ+2π/3或2kπ-2π/3,则π/5+x=2kπ+2π/3或π/5+x=2kπ-2π/3,解一下就可以了。