f(x)=2sin(2x+⊓/6)+a+1(a为常数) 当x∈[0,⊓/2]时,f(x)最大值为4,求a的值.
问题描述:
f(x)=2sin(2x+⊓/6)+a+1(a为常数) 当x∈[0,⊓/2]时,f(x)最大值为4,求a的值.
答
f(x)=2sin(2x+⊓/6)+a+1(a为常数) 当x∈[0,⊓/2]时,f(x)最大值为4,求a的值.