lim n趋向于无穷 2^n sin(x/2^n)
问题描述：
lim n趋向于无穷 2^n sin(x/2^n)
X为不等于0的常数
答
2^n sin(x/2^n)= [sin(x/2^n)/(x/2^n)]*x,n趋向于无穷大时,x/2^n趋向于无穷小,于是,整个式子趋向于x.
lim n趋向于无穷 2^n sin(x/2^n)
X为不等于0的常数
2^n sin(x/2^n)= [sin(x/2^n)/(x/2^n)]*x,n趋向于无穷大时,x/2^n趋向于无穷小,于是,整个式子趋向于x.